3x^2+29x-7.3=0

Solution for 3x^2+29x-7.3=0 equation:

3x^2+29x-7.3=0

a = 3; b = 29; c = -7.3;
Δ = b2-4ac
Δ = 292-4·3·(-7.3)
Δ = 928.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{928.6}}{2*3}=\frac{-29-\sqrt{928.6}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{928.6}}{2*3}=\frac{-29+\sqrt{928.6}}{6}
$